gem=Borgloon Borgloon Borgloon xquery version '3.0'; let $context := doc($db:context) let $howmany := 1000 let $lemmata := $context//lemma[geo//gem[matches(.,'^Borgloon$','i')]] return <result lem='{count($lemmata)}' atts='{count($lemmata/following-sibling::att)}' shown='{$howmany}'> { for $i in 1 to min(($howmany, count($lemmata))) let $lem := $lemmata[$i] order by $lem/vorm return <entry> {$lem} {$lem/following-sibling::att} </entry> } </result> Borgloon Borgloon Zie meer vormen bij Loon, het graafschap waarvan Borgloon de zetel was Lon 1078 kop. 13e I Lc n° 26 Lon ± 1200 Av A 65 Los (1147-55) H T 54 Los 1154 H L Bushoven Borgloon Bushoue 1147 kop. 13e I Je 14 Bushoue 1186 I Je 29 Rullingen Borgloon Rolengen 1135 Av A 2 Rolingen 1213 Av A 88